SOLUTION: Determine whether the square root of 77 is rational or irrational. Answer: A) Irrational B) Rational I say irrational since there is no square. ~~~~~~~~~~~~~~~~~~

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Question 99554: Determine whether the square root of 77 is rational or irrational. Answer: A) Irrational B) Rational
I say irrational since there is no square.
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Determine if (a square root symbol with a - inside it) is rational or irrational. Answer: A) Irrational B) Rational
I say: A) Irrational There is a negative symbol, also there is no number.
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Find the altitude of the triangle.
the sides (height) are each 13 and the base (bottom) is 10.
Answer: ????
This one I can not find a formula in my books for solving this.
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Evaluate (the square root symbol with 9 over 16 inside it) if possible.
I say not possible since it is not a whole number with a solution.
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Evaluate (small 3 next to the square root symbol with 1 over 64 inside it) if possible.
I say not possible since it is not a whole number with a solution.
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Am I on the right track? This is a large assignment and due tonight. These are the only ones I am doubting myself on and need your help. Thanks! ;-)

Found 2 solutions by stanbon, timmy1729:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Determine whether the square root of 77 is rational or irrational. Answer: A) Irrational B) Rational
I say irrational since there is no square.
Correct: It is irrational because 77 is not a perfect square.
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Determine if (a square root symbol with a - inside it) is rational or irrational. Answer: A) Irrational B) Rational
I say: A) Irrational There is a negative symbol, also there is no number.
It is neither rational nor irrational; it is a complex or imaginary number.
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Find the altitude of the triangle.
the sides (height) are each 13 and the base (bottom) is 10.
Answer: ????
This one I can not find a formula in my books for solving this.
Draw an altitude from the vertex to the base (side 10)
You get two right triangles:
altitude^2 + 5^2 = 13^2
altitude = sqrt(13^2-5^2) = sqrt144 = 12
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Evaluate (the square root symbol with 9 over 16 inside it) if possible.
I say not possible since it is not a whole number with a solution.
sqrt(9/16) = [sqrt(9)]/[sqrt(16)] = 3/4
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Evaluate (small 3 next to the square root symbol with 1 over 64 inside it) if possible.
I say not possible since it is not a whole number with a solution.
cube root of (1/64) = [cube root of 1]/[cube root of 64] = 1/4
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Cheers,
Stan H.
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Answer by timmy1729(23) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%2877%29 is irrational. For a number to be rational, it must be able to be expressed as a fraction of two integers a%2Fb in lowest terms(prime numbers).
One major thing to know, and you should investigate this for yourself, is that there is no prime number that will have a rational square root. 77 is a product of 11 and 7, both are primes and that means that it will not have a rational square root.
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Is sqrt%28-x%29 rational or irrational? Well, that all depends on the x. It will definitely have a complex root(imaginary), but that doesn't mean that it will be irrational. It all depends on the x for the same reason in the first question.
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Is that a right triangle? And what do you mean by altitude in regards to the triangle?
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The rule is sqrt%28a%2Fb%29+=+sqrt%28a%29%2Fsqrt%28b%29 so your answer is sqrt%289%29%2Fsqrt%2816%29+=+3%2F4. This also applies to your next question.
The cube root of 1/64. Same thing as above except for cube roots. The cube root of 1 = 1; the cube root of 64 = 4. So the cube root of 1/64 = 1/4.