SOLUTION: Find the value sin2 x on the interval (3pi/2, 2pi) given tan x = -3

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Question 971582: Find the value sin2 x on the interval (3pi/2, 2pi) given tan x = -3
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the value sin2 x on the interval (3pi/2, 2pi) given tan x = -3
tanx=-3/1
hypotenuse of reference right triangle=√(-3)^2+1=√10
sinx=-3/√10
cosx=1/√10
sin(2x)=2sinxcosx=2*(-3/√10)(1/√10)=-6/10=-3/5