SOLUTION: How do you factor x^4 +x^2*y^2+y^4 into (x^2+xy+y^2)(x^2-xy+y^2)? Thank you.

Algebra ->  Test  -> Lessons -> SOLUTION: How do you factor x^4 +x^2*y^2+y^4 into (x^2+xy+y^2)(x^2-xy+y^2)? Thank you.       Log On


   



Question 888254: How do you factor x^4 +x^2*y^2+y^4 into (x^2+xy+y^2)(x^2-xy+y^2)? Thank you.

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E4+%2Bx%5E2y%5E2%2By%5E4

We recognize that if there were a 2 coefficient on the
middle term, the expression with be a perfect square
trinomial.  We can make it have a coefficient of 2 by
adding x%5E2y%5E2.  But if we do that we'll have to also
subtract x%5E2y%5E2 to offset.

But that's OK for then we'll have the difference of 
two squares, and we know how to factor that.

So we add x%5E2y%5E2 to the middle term to make it 
2x%5E2y%5E2 and then subtract x%5E2y%5E2:

x%5E4%2B2x%5E2y%5E2%2By%5E4-x%5E2y%5E2

%28x%5E4%2B2x%5E2y%5E2%2By%5E4%29-x%5E2y%5E2

factor the first term as a perfect square and write the
second term as a square

%28x%5E2%2By%5E2%29%5E2-%28xy%29%5E2

which is the difference of two squares, and factors
like A%5E2-B%5E2=%28A-B%29%28A%2BB%29 with A=%28x%5E2%2By%5E2%29 and B=xy:

%28%28x%5E2%2By%5E2%29-xy%29%28%28x%5E2%2By%5E2%29%2Bxy%29

Remove the inner parentheses:

%28x%5E2%2By%5E2-xy%29%28x%5E2%2By%5E2%2Bxy%29

Write in descending order of x and ascending order of y:

%28x%5E2-xy%2By%5E2%29%28x%5E2%2Bxy%2By%5E2%29

Edwin