SOLUTION: the length of a rectangle is 4 less than twice its width. the area is 70 square inches. find the dimensions of the rectangle
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Hi,
the length of a rectangle is 4 less than twice its width
A = = (2x-4)x = 70 in^2
2x^2 - 4x - 70 = 0
(2x+ 10)(x -7 ) = 0 x = 7 (Tossing out the negative solution for unit measure)
width is 7in and length is 10in