SOLUTION: how can i understand foiling and factoring better?

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Question 704297: how can i understand foiling and factoring better?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Factoring takes practice and it is hard work.
The good news is that factoring gets easier with practice, and it is a very efficient way to solve some quadratic equations.
The bad news is that factoring keeps coming up in math, from rational functions and quadratic equations all the way to calculus.
I will show you my strategies, along with the rationale behind it.
Understanding the rationale helps me remember procedures without having to memorize "recipes" that make no sense to me.
There will be too many words, but I'll use more pictures as it gets too complicated for just words..

I assume you know that the first thing to do when factoring a complicated expression is to look for common factors.
If you have a polynomial like x%5E3-5x%5E2-6x, with x in all the terms,
you would first "take out the common factor" x, as in
x%5E3-5x%5E2-6x=x%28x%5E2-5x-6%29

FOIL is an acronym teachers use to help you remember all the terms when multiplying two binomials.
When multiplying the binomials F%2BS times f%2Bs
you get a sum of all four possible products:
%28F%2BS%29%28f%2Bs%29=F%2Af%2BF%2As%2BS%2Af%2Bs%2Af
In the acronym FOIL,
F stand for First terms multiplied make Ff
O stands for Outside terms multiplied make Fs
I L stands for stands for Inside terms multiplied make Sf
Last term multiplied make sf
Thinking of FOIL makes sure you include all four products, just once each, and nothing else.
In %28x%2B7%29%28x-2%29, the first x and -2 are the Outside terms.
The 7 and the x that appear together in the middle are the Inside terms
x%5E2 is the First terms multiplied,
-2x is the Outside terms multiplied,
7x is the Inside terms multiplied
After the "foiling" often comes the "collecting like terms", so after
%28x%2B7%29%28x-2%29=x%5E2-2x%2B7x-14
you add together the terms in x, -2x and 7x to get
-2x%2B7x=5x
and then you have
%28x%2B7%29%28x-2%29=x%5E2-2x%2B7x-14=x%5E2%2B5x-14

Factoring x%5E2-5x-6 is "unfoiling".
You know that the x%5E2 is the product of two first terms that must have been x in both binomials.
You know that the -6 term is the product of two last terms, and it is not that clear what those two last terms were.
There are several possibilities (four to be specific):
%286%29%28-1%29=-6 %28-6%29%281%29=-6 %283%29%28-2%29=-6 and %28-3%29%282%29=-6
In the foiling, the last terms of the binomial were also used as factors in the Outside and Inside products to make two terms in x.
In those two terms in x the last terms of the binomial appeared as coefficients in front of x.
The problem is that the two terms in x from the foiling were already "collected" together into the -5x term,
so the coefficients were added together to get -5.
We go back to the four possibilities and see what pair adds up to -5:
%286%29%2B%28-1%29=5 %28-6%29%2B%281%29=-5 %283%29%2B%28-2%29=1 and %28-3%29%2B%282%29=-1
so the two last terms must be %28-6%29 and %281%29.
So the factoring is
x%5E2-5x-6=%28x-6%29%28x%2B1%29

A PICTURE:
In the picture below, the large square represents the product %28a%2Bb%29%28c%2Bd%29=ac%2Bad%2Bbc%2Bbd.
It is what happens when a patio a tiles long by c tiles wide
is enlarged by adding b rows of tiles to the length and d rows to the wdith.
Foiling is multiplying the side measures to get the area of the rectangle.

The figure below illustrates %283x%2B2%29%285x-4%29=15x%5E2-12x%2B10x-8=15x%5E2-2x-8


Factoring is figuring out the rectangle sides from the area.
The figures below illustrates factoring 15x%5E2-2x-8
I will pretend that I do not know what the factors were as I try to undo the multiplication.
If you multiply together opposite corners, you find that they are the same.
%28acx%5E2%29%28bd%29=abcdx%5E2 and %28bcx%29%28adx%29=abcdx%5E2
so the bcx and adx that we are looking for must be factors of
%2815x%5E2%29%28-8%29=-120x%5E2
We look for pairs of factors that multiply to 15%2A8=120 without worrying much about signs, or about the x.
I know that 1,2,3,4,5,6,8,10,and 12 are factors because they divide 120 evenly).
Dividing 120 by each of the small,easy to find factors, I find the matching larger factors.
120=1%2A120=2%2A60=3%2A40=4%2A30=5%2A24=6%2B20=8%2A15=10%2A12
When I get to 12 I realize that 12%2A10 involves the same pair of factors I had already found as 10%2A12, so I know I have found all the factors.
Because the product has a minus sign, I know that one of the factors must have a minus sign.
Because they must add to the -2 in -2x, I figure that I am looking for a pair of factors that differ by 2 and I am going to give the minus sign to the larger factor.
12-10=2 is the answer
15-8=7 does not work, and neither do the other pairs.
-12 and 10 are the coefficients I am looking for.
I fill the bcx and adx squares with -12x and 10x.
It does not matter where I put each one.

Now I need to figure common factors for each row and column. Those common factors will replace the question marks.
I start with what seems more obvious to me, whatever I can figure out faster.
The 15x%5E2 and 10x in the left column share 5x as a common factor, so I put it above the left column.
The 15x%5E2 and -12x in the top row share 3x as a common factor, so I put it to the left of the top row. I could also have figured it, from what I already knew, as
15x%5E2%2F5x=3x.
The other question marks, I can figure out from what I already know:
-12x%2F3x=-4 goes above -12x and
10x%2F5x=2 goes above 10x.


SPECIAL PRODUCTS:
There are special products that you end up remembering after a while, and are represented by the "formulas" below.
Square of a binomial:
%28a%2Bb%29%5E2=a%5E2%2B2ab%2Bb%5E2
Difference of squares:
a%5E2-b%5E2=%28a%2Bb%29%28a-b%29
That one is easy to explain because when you FOIL, the O and I products cancel out, so your FOIL turns into FL (I cal that Florida).
Difference of cubes:
a%5E3-b%5E3=%28a%5E2%2Bab%2Bb%5E2%29%28a-b%29
Sum of cubes:
a%5E3%2Bb%5E3=%28a%5E2-ab%2Bb%5E2%29%28a%2Bb%29