SOLUTION: Hello professor. I need help finding the horizontal adymptote of h(x)= 2x^2-8x-6/7x^2-5x+5 Thank you!
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Question 689672
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Hello professor. I need help finding the horizontal adymptote of h(x)= 2x^2-8x-6/7x^2-5x+5
Thank you!
Answer by
stanbon(75887)
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You can
put this solution on YOUR website!
I need help finding the horizontal adymptote of h(x)= 2x^2-8x-6/7x^2-5x+5
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HA: y = (2x^2)/(7x^2) = 2/7
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Cheers,
Stan H.