SOLUTION: The age of a man is 4 times the sum of the ages of his three children and in 8 years it will be twice the sum. What is the present age of the man?

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Question 628769: The age of a man is 4 times the sum of the ages of his three children and in 8 years it will be twice the sum. What is the present age of the man?
Answer by graphmatics(170) About Me  (Show Source):
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Let x be the age of the man. Let y be the sum of the ages of the 3 children. Then x=4y x+8=2*(y+3*8)
x-4y=0 x-2y=-8+48 We solve this system
Solved by pluggable solver: Linear System solver (using determinant)
Solve:
+system%28+%0D%0A++++1%5Cx+%2B+-4%5Cy+=+0%2C%0D%0A++++1%5Cx+%2B+-2%5Cy+=+40+%29%0D%0A++

Any system of equations:


has solution

or



(x=80, y=20}