SOLUTION: how do i write 2 log 2 + log 3 - log 6 as a single log?
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Question 595745
:
how do i write 2 log 2 + log 3 - log 6 as a single log?
Answer by
nerdybill(7384)
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Applying "log rules":
2 log 2 + log 3 - log 6
log 2^2 + log 3 - log 6
log 4 + log 3 - log 6
log (4*3) - log 6
log 12 - log 6
log 12/6
log 2