Question 591605: (3x^3y^-2)(-2xy^3)^-1
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! (3x^3y^-2)(-2xy^3)^-1 is your expression.
since, in general, x^-a = 1/x^a, this expression can become:
(3x^3y^-2) / (-2xy^3)
since, in general, (a*b)/(c*d) is the same as (a/c) * (b/d), this expression can become:
-(3/2) * (x^3/x) * (y^-2/y^3)
since, in general, x^a / x^b is equal to x^(a-b), this expression can become:
-(3/2) * (x^3-1) * (y(-2-3) which can be simplified to:
-(3/2) * x^2 * y^-5
since, in general, x^-a = 1/x^a, this expression can become:
-(3/2) * x^2 * 1/y^5
since, in general, (a/c) * (b/d) is the same as (a*b) / (c*d), this expression can become:
(-3*x^2*1) / (2*y^5) which can be simplified to:
(-3x^2)/(2y^5)
that's your solution.
you can confirm the solution is good by picking value for x and for y and using those values in the original equation and the final equation.
if the solution comes out the same, then you did good.
you can use your calculator to perform the calculations.
i did with the values of x = 5 and y = 7.
i got:
original equation equals: .0022312132
final equation equals: .0022312132
they're the same so the original equation is equivalent to the final equation so we're good.
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