SOLUTION: A rectangle is twice as long as it is wide. If both it's dimensions are increased by 4 m it's area is increased by 88 m^2. Find the dimensions of the original rectangle.
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Question 527107: A rectangle is twice as long as it is wide. If both it's dimensions are increased by 4 m it's area is increased by 88 m^2. Find the dimensions of the original rectangle. Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! L = 2W
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(L+4)(W+4) = L*W + 88
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Substitute L = 2W
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(2W +4)(W +4) = 2W*W +88
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2W^2 +8W + 4W + 16 = 2W^2 + 88
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2W^2 +8W + 4W -2W^2 = 88 -16
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12W = 72
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W = 6 m = original width
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L = 2W = 12 m = original length
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Check the solution to make sure it's the answer.
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L*W = 72 = area of the original rectangle
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(L+4)(W+4) = 16*10 = 160 m^2
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160 -72 = 88 m^2
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Correct.
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Done.
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