SOLUTION: how to solve a system by substitution?
problems:
1) y= 6x + 13 and y= -4x - 17
2) y= -3 and 2x + 8 = -12
3) y= 8x - 16 and -2x + 2y = 10
4) x + 6y = -18 and 2x + y = 10
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-> SOLUTION: how to solve a system by substitution?
problems:
1) y= 6x + 13 and y= -4x - 17
2) y= -3 and 2x + 8 = -12
3) y= 8x - 16 and -2x + 2y = 10
4) x + 6y = -18 and 2x + y = 10
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Question 465382: how to solve a system by substitution?
problems:
1) y= 6x + 13 and y= -4x - 17
2) y= -3 and 2x + 8 = -12
3) y= 8x - 16 and -2x + 2y = 10
4) x + 6y = -18 and 2x + y = 10 Answer by solver91311(24713) (Show Source):
Problem 1: You have two expressions in terms of that are both equal to , so set the two expressions equal to each other. In other words, take the right hand side of your first equation and SUBSTITUTE the expression in place of the in the second equation, thus:
Solve the resulting single variable equation for . Use the value calculated for and substitute that value in place of in either of the original equations. Solve the resulting single variable equation for . The solution set for the system is the ordered pair using the values you calculated.
To check your work, take the values in the ordered pair and substitute them for the variables in the OTHER equation. If the solution is correct, the result will be a true statement.
Problems 2, 3, and 4: You only get to ask one question per post. Did you simply not read the instructions or do you think you are somehow special so that the rules don't apply in your case? Just curious.
John
My calculator said it, I believe it, that settles it
