SOLUTION: 38 year old man has an 11 year old daughter. Someday he will be twice as old as his daughter. How old will she be when this occurs?

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Question 453886: 38 year old man has an 11 year old daughter. Someday he will be twice as old as his daughter. How old will she be when this occurs?
Found 3 solutions by stanbon, rwm, Alan3354:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website!
38 year old man has an 11 year old daughter. Someday he will be twice as old as his daughter. How old will she be when this occurs?
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Now:
father = 38
daughter = 11
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Someday:
father = 38+x
daughter = 11+x
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Equation:
(38+x) = 2(11+x)
38 +x = 22 + 2x
15 = x
----
Daughter's ang then: 11+x = 11+15 = 26
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Cheers,
Stan H.

Answer by rwm(914)   (Show Source):
You can put this solution on YOUR website!
38+x=2*(11+x)
38+x=22+2x
16=x
she will be 11+16=27
He will be 54=38+16

Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website!
The difference is 27 yrs, and will always be 27 yrs.
--> when she's 27.