SOLUTION: factor completely 150r^2+360rg+216g^2

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Question 368802: factor completely
150r^2+360rg+216g^2
Found 2 solutions by stanbon, fractalier:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
factor completely
150r^2+360rg+216g^2
-------
= 2[75r^2 + 180rg + 108q^2]
----
= 2*3[25r^2 + 60rg + 36]
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= 6(5r+6)(5r+6)
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Cheers,
Stan H.
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Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
From 150r^2+360rg+216g^2,
we first pull out the greatest common factor, which is 6, and get
6(25r^2 + 60rg + 36g^2)
What remains is a perfect square trinomial...
= 6(5r + 6g)^2