Question 345968: 9x/4x+5x/6
Answer by haileytucki(390)   (Show Source):
You can put this solution on YOUR website! To factor:
(9x)/(4)*x+(5x)/(6)
Multiply (9x)/(4) by x to get (9x^(2))/(4).
(9x^(2))/(4)+(5x)/(6)
Factor out the GCF of (x)/(2) from each term in the polynomial.
(x((9x)/(2)))/(2)+(x((5)/(3)))/(2)
Factor out the GCF of (x)/(2) from (9x^(2))/(4)+(5x)/(6).
(x((9x)/(2)+(5)/(3)))/(2)
To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 6. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
(x(((9x)/(2)*(3)/(3)+(5)/(3)*(2)/(2))))/(2)
Complete the multiplication to produce a denominator of 6 in each expression.
(x(((27x)/(6)+(10)/(6))))/(2)
Combine the numerators of all expressions that have common denominators.
(x(((27x+10)/(6))))/(2)
Multiply x by (1)/(6) to get (x)/(6).
(((x)/(6))(27x+10))/(2)
Multiply 2 by 6 to get 12.
(x(27x+10))/(12)
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