Question 343183: 9x(9x^4 -3yx +2)
-12x^2y^3(-3 +2x^4y^5 -5)
5yx^5(-7x^2 +3xy^4 -xy)
Answer by haileytucki(390)   (Show Source):
You can put this solution on YOUR website! 9x(9x^(4)-3yx+2)
Arrange the variables alphabetically within the expression -3yx. This is the standard way of writing an expression.
9x(9x^(4)-3xy+2)
Multiply 9x by each term inside the parentheses.
81x^(5)-27x^(2)y+18x
-12x^(2)y^(3)(-3+2x^(4)y^(5)-5)
Subtract 5 from -3 to get -8.
-12x^(2)y^(3)(-8+2x^(4)y^(5))
Reorder the polynomial -8+2x^(4)y^(5) alphabetically from left to right, starting with the highest order term.
-12x^(2)y^(3)(2x^(4)y^(5)-8)
Multiply -12x^(2)y^(3) by each term inside the parentheses.
-24x^(6)y^(8)+96x^(2)y^(3)
5yx^(5)(-7x^(2)+3xy^(4)-xy)
Reorder the polynomial -7x^(2)+3xy^(4)-xy alphabetically from left to right, starting with the highest order term.
5yx^(5)(3xy^(4)-7x^(2)-xy)
Multiply 5yx^(5) by each term inside the parentheses.
15x^(6)y^(5)-35x^(7)y-5x^(6)y^(2)
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