SOLUTION: I am trying to solve by the elimination method. 0.3x-0.2y=4 0.2x+0.5y=-3

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Question 327003: I am trying to solve by the elimination method.
0.3x-0.2y=4
0.2x+0.5y=-3

Answer by jvan(28) About Me  (Show Source):
You can put this solution on YOUR website!
Through the elimination method, you can cancel out a variable. This will leave you with one variable in the equation. You can then solve the equation to find the value of the variable. Okay, lets start! =)
I will try to get rid of the x. I'll call 0.3x-0.2y=4 equation #1, and 0.2x%2B0.5y=-3 equation #2. If we want to get rid of the x variable, we have to make sure the number in front of the x terms in the two equations are the same. Right now they both have different numbers in front of them. Multiply equation #1 by 2 and equation #2 by 3 to get 0.6x-0.4y=8 and 0.6x%2B1.5y=-9. Notice that now we have 0.6 in front of the x terms, perfect! ^0^ Lets subtract the second equation from the first: %280.6x-0.4y%29-%280.6x%2B1.5y%29=8-%28-9%29%29. That becomes -1.9y=17. Divide both sides by -1.9 to get the y by itself: y=-8.9. You can pluy this back into either of the given equations to find x. I'll just choose equation #1 to plug into. It doesn't matter =) When we plug in y=-8.9, we get 0.3x-0.2y=4 becomes0.3x-0.2%28-8.9%29=4. Solving for x gives you x= 7.4! Now that you have found that y=-8.9 and x=7.5, you are done!
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