SOLUTION: really struggling on this use composite rule to differentiate the function f(x)=exp (2/3 sin x)

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Question 207751: really struggling on this
use composite rule to differentiate the function
f(x)=exp (2/3 sin x)
Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
use composite rule to differentiate the function
f(x)=exp (2/3 sin x)
------------------
Let u = (2/3 sin(x))
Then du = (2/3 cos(x))dx
----
f'(x) = [e^(2/3 sin(x)]*d/dx[(2/3 sin(x)]
f'(x) = [e^(2/3 sin(x))]
=============================================
Cheers,
Stan H.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=exp (2/3 sin x)
---------------
f'(x) = e^(2sin(x)/3)*(2cos(x)/3)
f'(x) = e%5E%282sin%28x%29%2F3%29%2A%282cos%28x%29%2F3%29
= %282%2F3%29%2Acos%28x%29%2Aexp%282sin%28x%29%2F3%29