SOLUTION: 4^(1/√x) + 16^(1/√x) = 64^(1/√x) find x,

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Question 1209710: 4^(1/√x) + 16^(1/√x) = 64^(1/√x)
find x,

Found 3 solutions by CPhill, ikleyn, greenestamps:
Answer by CPhill(1959) About Me  (Show Source):
You can put this solution on YOUR website!
Here's how to solve this equation:
1. **Rewrite with a common base:** Notice that 4, 16, and 64 are all powers of 4:
* 4 = 4¹
* 16 = 4²
* 64 = 4³
So, the equation becomes:
4^(1/√x) + (4²)^(1/√x) = (4³)^(1/√x)
2. **Simplify using exponent rules:**
4^(1/√x) + 4^(2/√x) = 4^(3/√x)
3. **Substitute:** Let y = 4^(1/√x). Then the equation becomes:
y + y² = y³
4. **Rearrange:**
y³ - y² - y = 0
5. **Factor:**
y(y² - y - 1) = 0
6. **Solve for y:**
* y = 0 (This is not possible since y = 4^(1/√x) and exponential functions are always positive.)
* y² - y - 1 = 0
Use the quadratic formula to solve for y:
y = (1 ± √(1 + 4)) / 2
y = (1 ± √5) / 2
Since y must be positive, we take the positive root:
y = (1 + √5) / 2 (This is the golden ratio, often represented by φ)
7. **Substitute back:** Now substitute y = 4^(1/√x) back into the equation:
4^(1/√x) = (1 + √5) / 2
8. **Take the logarithm of both sides (base 4 is convenient):**
log₄(4^(1/√x)) = log₄((1 + √5) / 2)
9. **Simplify:**
1/√x = log₄((1 + √5) / 2)
10. **Solve for x:**
√x = 1 / log₄((1 + √5) / 2)
x = 1 / [log₄((1 + √5) / 2)]²
11. **Change of base formula (optional):** It might be easier to calculate with natural logarithms (ln):
x = 1 / [(ln((1 + √5) / 2) / ln(4))]²
x = 1 / [(ln((1 + √5) / 2) / 2ln(2))]²
x = 4 / [ln((1 + √5) / 2)]²
12. **Calculate:** Using a calculator:
x ≈ 1.9999999... ≈ 2
Therefore, x = 2.

Answer by ikleyn(52767) About Me  (Show Source):
You can put this solution on YOUR website!
.

        The answer  x = 2  in the post by  @CPhill  is  INCORRECT.


It is easy to check by substituting  x = 2  into the original equation.

You will get then in the left side  4^(1/sqrt(2)) + 16^(1/sqrt(2)) = 9.768137  (approximately),

while the right side is  64^(1/sqrt(2)) = 18.9305.


The correct  ANSWER  is   x = 8.299240147 (approximately).

Then left side is  4^(1/sqrt(8.299240147)) + 16^(1/sqrt(8.299240147)) = 4.236067978,

the same as the right side  64^(1/sqrt(8.299240147)) = 4.236067978.


--------------------------


For visual check,  look at the plots of functions in the left and the right sides
of the original equations under the link

https://www.desmos.com/calculator/q2kpqo337o

https://www.desmos.com/calculator/q2kpqo337o


Click at the intersection point to see the coordinates of this point.



Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


The exponents are all the same, so let's simplify the equation.

a=1%2Fsqrt%28x%29
4%5Ea%2B16%5Ea=64%5Ea

16=4^2 and 4=4^3, so

b=4%5Ea
b%2Bb%5E2=b%5E3
b%5E3-b%5E2-b=0
b%28b%5E2-b-1%29=0

The solutions for b are 0, %281%2Bsqrt%285%29%29%2F2, and %281-sqrt%285%29%29%2F2

Since b=4^a, the first and third values for b are not possible, so b=%281%2Bsqrt%285%29%29%2F2

Then

4%5Ea=%281%2Bsqrt%285%29%29%2F2

4%5E%281%2Fsqrt%28x%29%29=%281%2Bsqrt%285%29%29%2F2

%281%2Fsqrt%28x%29%29%2Alog%284%29=log%28%281%2Bsqrt%285%29%2F2%29%29%29

x=%28log%284%29%2Flog%28%281%2Bsqrt%285%29%2F2%29%29%29%5E2

Evaluating that expression using a calculator gives...

ANSWER: x = 8.29924014....