SOLUTION: Let S = {1,2,3,...,18,19,20} be the universal set. Let sets A and B be subsets of S, where: Set A={2,3,5,6,7,11,12,13,14,16,17,19,20} Set B={3,6,7,11,13,14,16,17} LIS

Algebra ->  Test  -> Lessons -> SOLUTION: Let S = {1,2,3,...,18,19,20} be the universal set. Let sets A and B be subsets of S, where: Set A={2,3,5,6,7,11,12,13,14,16,17,19,20} Set B={3,6,7,11,13,14,16,17} LIS      Log On


   

Question 1195638: Let S = {1,2,3,...,18,19,20} be the universal set.
Let sets A and B be subsets of S, where:
Set A={2,3,5,6,7,11,12,13,14,16,17,19,20}
Set B={3,6,7,11,13,14,16,17}

LIST the elements in the set
A∪B:A∪B= {____ }
LIST the elements in the set
A∩B:A∩B= {____}

Enter the elements as a list, separated by commas. If the result is the empty set, enter DNE
Answer by Solver92311(821) About Me  (Show Source):
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The union of two sets contains elements that are in one set, the other set, or both. For example: The Union of A and B contains the element 2 because 2 is an element of A and it contains the element 6 because 6 is an element of both A and B. The element 1 of the universal set is not an element of A union B because neither A nor B contain the element 1. Since all of the elements of B are also in A, the union set is identical to A

The intersection of two sets is the set of elements that are in both of the sets. For example, the element 2 is not in the intersection because 2 is only in set A, and the element 1 is not in the intersection because 1 is not in either A or B. Since all of the elements in B are also in A, the intersection set is identical to set B.


John

My calculator said it, I believe it, that settles it

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