SOLUTION: Determine the value of x , where 0 ≤ x ≤ π , for which the curve y = 2cosx + 3sinx has a stationary point and determine the nature of this point.

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Question 1192776: Determine the value of x , where 0 ≤ x ≤ π , for which the curve y = 2cosx + 3sinx has a stationary point and determine the nature of this point.
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


f%28x%29=2cos%28x%29%2B3sin%28x%29

df%2Fdx=-2sin%28x%29%2B3cos%28x%29

d%5E2f%2Fdx%5E2=-2cos%28x%29-3sin%28x%29

The stationary point is where the derivative is zero.

-2sin%28x%29%2B3cos%28x%29=0
2sin%28x%29=3cos%28x%29
sin%28x%29%2Fcos%28x%29=3%2F2
x+=+tan%5E%28-1%29%283%2F2%29 ~ 0.983 radians

There is little value in evaluating the function by hand when x has the value arctan(3/2); use a graphing calculator to find the approximate y value at the stationary point.

The nature of the stationary point is determined by the sign of the second derivative. The graphing calculator will show that the stationary point is a maximum.

However, you can tell that the stationary point will be a maximum by looking at the second derivative of the function. The stationary point is when x is between 0 and pi/2, so we are in the first quadrant, where sin(x) and cos(x) are both positive; so the sign of the second derivative is clearly negative, which means the stationary point is a maximum.

A graph, for x from -pi/2 to 3pi/2, showing a maximum at approximately (1,3.6)....

graph%28400%2C400%2C-pi%2F2%2C3pi%2F2%2C-5%2C5%2C2cos%28x%29%2B3sin%28x%29%29