SOLUTION: Find the values of x, where 0° < x <180° such that sin(3x+70°) = 0.2

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Question 1190283: Find the values of x, where 0° < x <180° such that sin(3x+70°) = 0.2
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Find the values of x, where 0+%3C+x+%3C180° such that sin%283x%2B70%29+=+0.2

+sin%283x%2B70%29+=+0.2
3x%2B70+=++sin%5E-1%280.2%29

solve 3x%2B70%C2%B0+=180-++sin%5E-1%280.2%29%2B360%2An

x=360%2An%2F3%2Bsin%5E-1%280.2%29%2F3-23.33333°
x=60-23.33333%2B360%2An%2F3-sin%5E-1%280.2%29%2F3°


Solutions for the range 0%3Cx%3C180°:

Radians:
x=0.57283
x=1.75427
x=2.66722

Degrees:
x=32.8207°
x=100.51°
x=152.82°