SOLUTION: Find the values of x, where 0 < x < 2π , which satisfy sec(x - π/6) = 3

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Question 1190282: Find the values of x, where 0 < x < 2π , which satisfy sec(x - π/6) = 3
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

sec%28x+-+pi%2F6%29+=+3+where 0+%3C+x+%3C+2pi

sec%28x+-+pi%2F6%29+=+3
x+-+pi%2F6=+sec%5E-1%283%29
x+=+sec%5E-1%283%29%2Bpi%2F6

solutions:
x=sec%5E-1%283%29%2B2pi%2An%2Bpi%2F6
x=2pi+-sec%5E-1%283%29%2B2pi%2An%2Bpi%2F6


solutions for 0+%3C+x+%3C+2pi
in radians:
x+=++pi%2F6+%2Bcos%5E-1%281%2F3%29
x+=+%2813pi%29%2F6+-+cos%5E%28-1%29%281%2F3%29

in degrees:

x=100.53°
x=319.47°