SOLUTION: Find all the angles of x for 0° < x < 360° which satisfy cot(2x+10°) = -0.5

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Question 1190280: Find all the angles of x for 0° < x < 360° which satisfy cot(2x+10°) = -0.5
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Find all the angles of x for 0+%3C+x+%3C+360° which satisfy cot%282x%2B10%29+=+-0.5

cot%282x%2B10%29+=+-0.5
2x%2B10+=+cot%5E-1%28-0.5%29
x++=++cot%5E-1%28-0.5%29-10°

solutions:

x+=+%2817pi%29%2F36+-+%281%2F2%29+cot%5E%28-1%29%281%2F2%29
x+=+%2835pi%29%2F36+-+%281%2F2%29+cot%5E%28-1%29%281%2F2%29
x+=+%2853pi%29%2F36+-+1%2F2+cot%5E%28-1%29%281%2F2%29
x+=+%2871pi%29%2F36+-+%281%2F2%29+cot%5E%28-1%29%281%2F2%29

degrees:
x=116.72°

x=143.28°
x=233.28°
x=323.28°