Question 1163664: . Determine the value(s) of k such that the angle between the vector
a = (1, 1, k) and b = (1, 0, 1) is 45°.
There are little arrows above vectors a and b.. Thank you.
Answer by ikleyn(52754) (Show Source):
You can put this solution on YOUR website! .
Use the formula
= , (1)
where (a*b) is the scalar product of the vectors and |a| and |b| are the lengths of these vectors.
is the angle between the given vectors.
In your case
(a*b) = 1*1 + 1*0 + k*1 = k+1;
|a| = = ;
|b| = = .
So, your equation (1) becomes
= .
Simplify it step by step
=
1 =
= k+1
k^2 + 2 = (k+1)^2
k^2 + 2 = k^2 + 2k + 1
2 = 2k + 1
2 - 1 = 2k
1 = 2k
k = = 0.5. ANSWER
Solved.
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For the angle between two vectors in 2D coordinate plane, see the lessons
- Introduction to dot-product
- Formula for Dot-product of vectors in a plane via the vectors components
- Dot-product of vectors in a coordinate plane and the angle between two vectors
- Perpendicular vectors in a coordinate plane
- Solved problems on Dot-product of vectors and the angle between two vectors
- Properties of Dot-product of vectors in a coordinate plane
- The formula for the angle between two vectors and the formula for cosines of the difference of two angles (*)
in this site.
From this list, the most relevant to your problem is the lesson marked (*)
There are also short lessons of the "HOW TO . . . " type on Dot-product:
- HOW TO find dot-product of two vectors in a plane
- HOW TO find scalar product of two vectors in a coordinate plane
- HOW TO find the angle between two vectors in a coordinate plane
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Dot-product for vectors in a coordinate plane".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
==============
These lessons guide you through the 2D case.
The 3D case is totally/fully analogous; so, if you know 2D-case, then 3D is simply easy variation of it . . .
Please let me know if everything was clear to you and if my post and the referred lessons were useful.
If after reading my post you will have questions, do not hesitate to post them to me.
If you do, then please refer to the ID number of this problem, which is 1163664.
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It is how this forum works.
So, mentioning this ID is NECESSARY, if you want to have two-way communication with me.
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