SOLUTION: A gridding wheel 0.35m in diameter rotates at 2200 RPM (anglular velocity 230 rad/Sec) Calculate the acceleration point on the edge of girding wheel.

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Question 1161487: A gridding wheel 0.35m in diameter rotates at 2200 RPM
(anglular velocity 230 rad/Sec) Calculate the acceleration point on the edge of girding wheel.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A gridding wheel 0.35m in diameter rotates at 2200 RPM
(anglular velocity 230 rad/Sec) Calculate the acceleration point on the edge of girding wheel.
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I suspect it's a grinding wheel.
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Using 230 rad/sec for w:
a+=+w%5E2%2Ar
a = 230^2*0.35/2
a = 9257.5 m/sec/sec