SOLUTION: Find the slope of the line tangent to the curve y^2=12x at (3,6)

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Question 1084583: Find the slope of the line tangent to the curve y^2=12x at (3,6)
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
2yy'=12, using implicit differentiation.
yy'=6
y'=6/y
when y=6, y'=1
use point slope formula y-y1=m(x-x1), m slope (x1,y1) point
y-6=x-3
y=x+3; slope is 1 ANSWER
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Csqrt%2812x%29%2C-sqrt%2812x%29%2Cx%2B3%29