SOLUTION: Please help me find the angle measurements of A, b, and {{{ a }}} for the triangle A = 150°, b = 4.8, a = 9.4. So far I have {{{ sin(150)/9.4 }}} = {{{ sin(150)/9.4 }}} sin(B) =

Algebra ->  Test  -> Lessons -> SOLUTION: Please help me find the angle measurements of A, b, and {{{ a }}} for the triangle A = 150°, b = 4.8, a = 9.4. So far I have {{{ sin(150)/9.4 }}} = {{{ sin(150)/9.4 }}} sin(B) =      Log On


   

Question 1077574: Please help me find the angle measurements of A, b, and +a+ for the triangle A = 150°, b = 4.8, a = 9.4.
So far I have +sin%28150%29%2F9.4+ = +sin%28150%29%2F9.4+ sin(B) = 4.8 * sin(150)/9.4 =~0.255319 C = 180 - (A+B) = 15.2075° +c%5E2+=+4.8%5E2+%2B+9.4%5E2+-+2+%2A+4.8+%2A+9.4+%2A+cos%28c%29+ +c%5E2+%2B+111.4+-+90.24cos%28c%29+
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Be sure that you draw the triangle according to the data given to you.

Law of Sines will allow you the equation, sin%28150%29%2F9.4=sin%28B%29%2F4.8, and this lets you find the value for interior angle at point B.
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sin%28B%29=4.8%2Asin%28150%29%2F9.4

sin%28B%29=%284.8%2F9.4%29sin%28150%29
(and sin of 150 degrees is same as sin of 30 degree.)

sin%28B%29=0.5%284.8%2F9.4%29

sin%28B%29=0.255319

meas. angle at B, highlight%2814.792%2Adegrees%29.


Find angle measure at C.
C%2BA%2BB=180
C%2B150%2B14.792=180
C=180-150-14.792
highlight%28C=15.208%2Adegrees%29
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The Law Of Cosines IS NOT NECESSARY for the problem.


You can again make use of Law Of Sines to find side length c.