SOLUTION: What are the remaining sides of the triangle A = 25°, b = 28, a = 18?
I found {{{ b }}} by equating,
sin(25)18=sin(b)28 18sin(b)=28sin(25) sin(b)=28sin(25)18
b=0.71737138
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-> SOLUTION: What are the remaining sides of the triangle A = 25°, b = 28, a = 18?
I found {{{ b }}} by equating,
sin(25)18=sin(b)28 18sin(b)=28sin(25) sin(b)=28sin(25)18
b=0.71737138
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Question 1076728: What are the remaining sides of the triangle A = 25°, b = 28, a = 18?
I found by equating,
sin(25)18=sin(b)28 18sin(b)=28sin(25) sin(b)=28sin(25)18
b=0.71737138 Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! No. Setup the equation correctly. You should find the interior angle at B to be 41.102 degrees, so you should determine that angle at C to be 113.898 degrees.
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