SOLUTION: What are the remaining angles for Triangle of A = 25°, b = 28, a = 18?
sin(25)18=sin(b)28 18sin(b)=28sin(25) sin(b)=28sin(25)18
b=0.71737138
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sin(25)18=sin(b)28 18sin(b)=28sin(25) sin(b)=28sin(25)18
b=0.71737138
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Question 1076625: What are the remaining angles for Triangle of A = 25°, b = 28, a = 18?
sin(25)18=sin(b)28 18sin(b)=28sin(25) sin(b)=28sin(25)18
b=0.71737138 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! What are the remaining angles for Triangle of A = 25°, b = 28, a = 18?
sin(25)18=sin(b)28
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sin(25)/18=sin(B)/28
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