SOLUTION: The sum of three numbers is 40. The difference between the largest and smallest is 12, and the largest is equal to the sum of the two smaller numbers. Find the numbers.

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Question 1059744: The sum of three numbers is 40. The difference between the largest and smallest is 12, and the largest is equal to the sum of the two smaller numbers. Find the numbers.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
A%2BB%2BC=40
C-A=12
C=A%2BB
Substituting 3 into 1,
C%2BC=40
2C=40
C=20
So then,
20-A=12
A=8
and
8%2BB%2B20=40
B=12