SOLUTION: 3y^3 - y^2 = 2y
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Question 1044102
:
3y^3 - y^2 = 2y
Answer by
jorel555(1290)
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3y³-y²-2y=0
y(3y²-y-2)=0
y(3y+2)(y-1)=0
y=0,-2/3,1 . ☺☺☺☺