SOLUTION: How would you go about finding when the percent of foreign ­born citizen was at its highest and when it was at its lowest percent since 1990? The U.S. population that was foreig

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Question 1036215: How would you go about finding when the percent of foreign ­born citizen was at its highest and when it was at its lowest percent since 1990?
The U.S. population that was foreign-born since 1900 can be modeled by +P%28t%29+=+0.00006t%5E3+-+0.007t%5E2+%2B+0.05t+%2B+14+ where t = 0 in 1990.
Here is the graph of the polynomial function: http://postimg.org/image/hz7mo786z/

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
+P%28t%29+=+0.00006t%5E3+-+0.007t%5E2+%2B+0.05t+%2B+14+ where t = 0 in 1990.
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Find the 1st derivative.
P'(t) = 0.00018t%5E2+-+0.014t+%2B+0.05+
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Solve the quadratic for t, the times of local max and min.
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 0.00018x%5E2%2B-0.014x%2B0.05+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-0.014%29%5E2-4%2A0.00018%2A0.05=0.00016.

Discriminant d=0.00016 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--0.014%2B-sqrt%28+0.00016+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-0.014%29%2Bsqrt%28+0.00016+%29%29%2F2%5C0.00018+=+74.0253073352042
x%5B2%5D+=+%28-%28-0.014%29-sqrt%28+0.00016+%29%29%2F2%5C0.00018+=+3.75247044257356

Quadratic expression 0.00018x%5E2%2B-0.014x%2B0.05 can be factored:
0.00018x%5E2%2B-0.014x%2B0.05+=+%28x-74.0253073352042%29%2A%28x-3.75247044257356%29
Again, the answer is: 74.0253073352042, 3.75247044257356. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+0.00018%2Ax%5E2%2B-0.014%2Ax%2B0.05+%29

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t = x + 1900
--> 1903 & 1974
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You can see on the graph the 1903 is the max and 1974 is the minimum.
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To determine whether it's a max or min, find the 2nd derivative of P(t)
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P"(t) = 0.00036t+-+0.014+
P"(3) = 0.00036t+-+0.014+ = -0.01292
< 0 --> maximum
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P"(74) = 0.01264
> 0 --> minimum