Question 1035652: Susan and Meaghan decide to meet at their favorite diner located near the Townsend Station. Susan leaves the Birchwood Station at 7:15 p.m. headed west on a train traveling 55 mi/h. Meaghan leaves the Meadowland Station at 7:30 p.m. headed east on a train traveling 70 mi/h. The two trains travel on parallel tracks and the distance between the Birchwood and Meadowland stations is 50 miles. If the girls get to the Townsend Station at the same time, at what time did their trains arrive? Express your answer as a time to the nearest minute.
Answer by jorel555(1290)   (Show Source):
You can put this solution on YOUR website! Since Susan leaves the Birchwood station 15 minutes before Meaghan leaves, she travels a distance of 55/60*15 miles, or 13.75 miles. The distance between the two of them is now 50-13.75, or 36.25 miles. Since they are traveling towards each other, we can add velocities, or 55+70=125 mph. 36.25/125=.29 hours, or 17.4 minutes after 7:30 p.m. arrival time, or 7:47 and 24 seconds, p.m.!!!!!!!!!!!
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