SOLUTION: Hello, I have been stuck on this problem for over an hour. Any help would be greatly appreciated! A certain ore yields an average of 61% iron. How much ore is needed to obtai

Question 938649: Hello,
I have been stuck on this problem for over an hour. Any help would be greatly appreciated!
A certain ore yields an average of 61% iron. How much ore is needed to obtain 1,220 lb of iron?
I know the answer is 2,000 but can't figure out how to get there.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
61% yield
If you need 61 lbs you need to have 100 lbs of ore
to get 1220 lbs
you need 100/61 *1220 = 2000 lbs

RELATED QUESTIONS
Please solve and show work. Any input on this problem would be GREATLY... (answered by kev82)

Hey! I have been working on this problem for awhile now & any help would be greatly... (answered by scott8148)

Hello everyone,I am having some trouble solving this problem. f(t) = {{{ 5sqrt(t) -... (answered by ikleyn,greenestamps)

Hello! I just need some help on solving this one problem since I can be barely sure of... (answered by mananth)

I have been stuck on this problem for three days now...anyone who could help will be... (answered by longjonsilver)

Hello, I am having some difficulty constructing this truth table. I have been working (answered by jim_thompson5910)

I am stuck on this problem, any help will be greatly appreciated. Two consecutive odd... (answered by stanbon,Alan3354)

Hello I'm having trouble setting this problem up. Any help would be appreciated. Thanks. (answered by ikleyn,josgarithmetic,MathTherapy)

Hello. My question is {{{i^-35}}}. This is a tough one for me, because i^2 is -1. Then (answered by Alan3354)