SOLUTION: The population of a town increased by 16 2/3% in 1990 and by 10% in 1991. If the population of the town at the beginning of 1990 was 30,000, what was it at the end of 1991?

Algebra ->  Percentages: Solvers, Trainers, Word Problems and pie charts -> SOLUTION: The population of a town increased by 16 2/3% in 1990 and by 10% in 1991. If the population of the town at the beginning of 1990 was 30,000, what was it at the end of 1991?       Log On


   

Question 1055713: The population of a town increased by 16 2/3% in 1990 and by 10% in 1991. If the population of the town at the beginning of 1990 was 30,000, what was it at the end of 1991?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
16 2/3% is 1/6
Population was 30,000 and increase of 1/6 is an increase of 5000. So the population in 1991 is 35,000.
That increases 10% that year, which is 3500, 10% of the new population. At the end of 1991, the population is 38,500.