SOLUTION: Solve 2log3x =1+log3(18-x)

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Question 911358: Solve 2log3x =1+log3(18-x)
Answer by MathLover1(20855) About Me  (Show Source):
You can put this solution on YOUR website!
2log%283%2C%28x%29%29+=+1%2Blog%283%2C%2818-x%29%29+... in base 10 will be
%282+log%28x%29%29%2F%28log%283%29%29+=+%28log%28%2818-x%29%29%29%2F%28log%283%29%29%2B1

2+log%28x%29=+log%283%29%2A%28log%28%2818-x%29%29%2Flog%283%29%29%2B1%28log%283%29%29



2+log%28x%29=+log%28%2818-x%29%29%2Blog%283%29

+log%28x%5E2%29=+log%28%283%2818-x%29%29%29

x%5E2=+3%2818-x%29

+x%5E2=+54-3x

x%5E2%2B3x-54=0

x%5E2-6x%2B9x-54=0

%28x%5E2-6x%29%2B%289x-54%29=0

x%28x-6%29%2B9%28x-6%29=0

%28x%2B9%29%28x-6%29=0

since log, we need only positive solution
if %28x-6%29=0 => x=6