SOLUTION: How do I get the exact real value of x from the equation: log (x-2) + log 8 = 1

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Question 968476: How do I get the exact real value of x from the equation: log (x-2) + log 8 = 1
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+log%28%28+x-+2+%29%29+%2Blog%28%28+8+%29%29+=+1+
If the base isn't shown, it must be +10+
+1+=+log%28%28+10+%29%29+
+log%28%28+x-+2+%29%29+%2B+log%28%28+8+%29%29+=+log%28%28+10+%29%29+
+log%28%28+%28+x-2+%29%2A8+%29%29+=+log%28%28+10+%29%29+
+%28+x-2+%29%2A8+=+10+
+8x+-+16+=+10+
+8x+=+26+
+x+=+13%2F4+
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check answer:
+13%2F4+=+3.25+
+log%28%28+3.25-+2+%29%29+%2Blog%28%28+8+%29%29+=+1+
+log%28%28+1.25+%29%29+%2B+log%28%28+8+%29%29+=+1+
+.09691+%2B+.90309+=+1+
+.99999998+=+1+
close enough because I rounded off