SOLUTION: 5^(-2x)=55^x is asking me to solve but I can't do change of base and if I introduce a log I feel like it will make the problem more confusing . Can you help thanks

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: 5^(-2x)=55^x is asking me to solve but I can't do change of base and if I introduce a log I feel like it will make the problem more confusing . Can you help thanks      Log On


   

Question 968265: 5^(-2x)=55^x is asking me to solve but I can't do change of base and if I introduce a log I feel like it will make the problem more confusing . Can you help thanks
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
5%5E%28-2x%29=55%5Ex
The only value for x that would make this an equation, is x = 0