SOLUTION: How do I graph y=2log(x-3)? I have the asymptope which is x=3

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Question 950668: How do I graph y=2log(x-3)? I have the asymptope which is x=3
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
I assume you have log base 10
y=2log%2810%2C%28x-3%29%29
first, the vertical asymptote of y =2log(x-3) is at x+=+3
you also need to remember that logs are not defined for negative x or for x+=+0,
so, the vertical asymptote is at x+=+3, you just start with x+=+4 because x=3 will give you log%280%29 which is y+=+-infinity, and work from there, using the definition of the log, make a table
x|....y=2log%2810%2C%28x-3%29%29
4|....0.......y=2log%2810%2C%284-3%29%29=0
5|....0.6...y=2log%2810%2C%285-3%29%29=0.6
6|....0.95.....y=2log%2810%2C%286-3%29%29=0.95
7|....1.2.......y=2log%2810%2C%287-3%29%29=1.2
plot these points and draw a line through