SOLUTION: How do I find x in the logarithmic equation (1/4)log base 5((x^2-8x+16)^2)=2?

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Question 928996: How do I find x in the logarithmic equation (1/4)log base 5((x^2-8x+16)^2)=2?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How do I find x in the logarithmic equation (1/4)log base 5((x^2-8x+16)^2)=2?
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log base 5((x^2-8x+16)^2) = 8
log%285%2C%28x%5E2-8x%2B16%29%5E2%29+=+8
2log%285%2C%28x%5E2-8x%2B16%29%29+=+8
log%285%2C%28x%5E2-8x%2B16%29%29+=+4
log%285%2C%28x-4%29%5E2%29+=+4
2log%285%2C%28x-4%29%29+=+4
log%285%2C%28x-4%29%29+=+2
log%285%2C%28x-4%29%29+=+log%285%2C5%5E2%29+=+log%285%2C25%29
x-4 = 25
x = 29