SOLUTION: Solve 5^(x^2+x) = 1

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Question 896968: Solve 5^(x^2+x) = 1
Found 2 solutions by thesvw, MathTherapy:
Answer by thesvw(77) About Me  (Show Source):
You can put this solution on YOUR website!
5%5E%28x%5E2%2Bx%29+=+1
Take log to the base 5.
Then you can take (x^2+x) infront
%28x%5E2%2Bx%29%2Alog5+=+log1
x%5E2+%2Bx=+0
x%28x%2B1%29=0
x=0 or x=+-1

Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!

Solve 5^(x^2+x) = 1


a%5Eb+=+1, when b = 0

Thus, for highlight%28highlight%285%5E%28x%5E2+%2B+x%29+=+1%29%29, 5%5Eo+=+1, and so: x%5E2+%2B+x+=+0______x(x + 1) = 0

Therefore, highlight_green%28x+=+0%29, or highlight_green%28x+=+-+1%29

You can do the check!! 



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