SOLUTION: My teacher wants the to solve the set of problems, but her being in Florida on vacation does not help me in any form or fashion....Please help log7 + log (n - 2) = log 6n log

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: My teacher wants the to solve the set of problems, but her being in Florida on vacation does not help me in any form or fashion....Please help log7 + log (n - 2) = log 6n log      Log On


   

Question 88625: My teacher wants the to solve the set of problems, but her being in Florida on vacation does not help me in any form or fashion....Please help
log7 + log (n - 2) = log 6n
log516 - log52t = log52
log5m = log5125
logy = log16 + log49
log6(b2 + 2) + log62 = 2
log3(5x+5) - log3(x2 - 1) = 0
log2(x - 2) + 5 = 8 - log2 4

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
log7 + log (n - 2) = log 6n
log (7(n - 2)) - log 6n = 0
log (7(n - 2)/6n) = 0
log ((7n - 14)/6n) = 0
(7n - 14)/6n = 10^0 = 1
7n - 14 = 6n
n = 14

The main idea is this:
log%2810%2Cx%29+-+log%2810%2Cx+-+1%29+=+log%2810%2Cx%2F%28x+-+1%29%29
log%2810%2Cx%29+%2B+log%2810%2Cx+-+1%29+=+log%2810%2Cx%28x+-+1%29%29
I will do two more:
log5m = log5125
5m = 5125
m = 1025
And:
log2(x - 2) + 5 = 8 - log2 4
log2(x - 2) = 3 - log2 2^2
log2(x - 2) = 3 - 2*log2 2
log2(x - 2) = 3 - 2*1
log2(x - 2) = 1
x - 2 = 2^1
x = 4
graph%28500%2C300%2C-2%2C6%2C-2%2C7%2Clog%282%2Cx+-+2%29+%2B+5%2C8+-+log%282%2C4%29%29