SOLUTION: Solve logx+log(x-3)=log108
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Question 876872
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Solve logx+log(x-3)=log108
Answer by
LinnW(1048)
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log(x)+log(x-3)=log(108)
log(x*(x-3)) = log(108)
x*(x-3) = 108
x^2 - 3x = 108
x^2 - 3x - 108 = 0
(x - 12)(x + 9) = 0
x = 12 or x = -9