SOLUTION: Solve the equation. Round to 2 decimal places if needed. log_7(x+6)-log_7(x-3)=log_74 Thanks in advance for the help.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve the equation. Round to 2 decimal places if needed. log_7(x+6)-log_7(x-3)=log_74 Thanks in advance for the help.      Log On


   

Question 859555: Solve the equation. Round to 2 decimal places if needed.
log_7(x+6)-log_7(x-3)=log_74
Thanks in advance for the help.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

log%287%2C%28x%2B6%29%29+-+log%287%2C%28x-3%29%29+-log%287%2C%284%29%29+=+0

log%287%2C%28+%28x%2B6%29%2F4%28x-3%29+%29%29+=+0   |  Note: 7^0 = 1, yes setting to zero is HUGE

%28x%2B6%29%2F4%28x-3%29+=+1

   x+6 = 4x-12

    18 = 3x

    x = 6