SOLUTION: I would like to know how to solve this please. log_6 (x-2) + log_6 3 = log_6 2

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Question 827892: I would like to know how to solve this please.
log_6 (x-2) + log_6 3 = log_6 2
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

log%286%2C%28x-2%29%29+%2B+log%286%2C3%29+=+log%286%2C2%29

log%286%2C%28x-2%29%2A3%29+=+log%286%2C2%29....since log of same base is equal, then

%28x-2%29%2A3+=+2 ....is equal too; so, all we need is to solve for x

x-2+=+2%2F3
x=+2%2F3%2B2
x=+2%2F3%2B6%2F3
x=+8%2F3