You can put this solution on YOUR website! log(base 3)(a-3)=1 + log(base 3)(a+1)
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log(base 3)(a-3)-log(base 3)(a+1)=1
but log(base x)(x)=1
Our equation becomes;
log(base 3)(a-3)-log(base 3)(a+1)=log(base 3)3
log(base 3)[(a-3)/(a+1)]=log(base 3)3
Divide through by log(base 3)
Cross multiply
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Divide through by -2