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log(3x+2) + log(x-1) =2
log(3x+2)(x-1)=2
log(3x+2)(x-1)=log(100)
(3x+2)(x-1)=100
3x^2-x-102=0
(3x+17)(x-6)=0
x=-17/3 (reject,(x-1)>0)
or
x=6
Check:
log(3x+2)=log(20)
log(x-1)=log(5)
log(20)+log(5)=2