SOLUTION: Find an equation to the tangent line to the curve at the given point. y=ln(x^2-6x+1) at (6,0) I got the answer y=6(x-0)+6 but it was wrong.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Find an equation to the tangent line to the curve at the given point. y=ln(x^2-6x+1) at (6,0) I got the answer y=6(x-0)+6 but it was wrong.      Log On


   

Question 804710: Find an equation to the tangent line to the curve at the given point.
y=ln(x^2-6x+1) at (6,0)

I got the answer y=6(x-0)+6 but it was wrong.
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!




Let



You can calculate for yourself.

John

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