SOLUTION: log 4x= log 5+log(x+1)

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Question 80251: log 4x= log 5+log(x+1)
Found 2 solutions by tutor_paul, MathTherapy:
Answer by tutor_paul(519) About Me  (Show Source):
You can put this solution on YOUR website!
log+4x=+log+5%2Blog%28%28x%2B1%29%29
First, get the x terms alone on one side of the equation:
log4x-log%28%28x%2B1%29%29=log5
You can use a log property to rewrite the left hand side:
log%28%284x%2F%28%28x%2B1%29%29%29%29=log5
Now you can raise 10 to each side of the equation, effectively cancelling out the logs:
4x%2F%28x%2B1%29=5
solve for x:
4x=5x%2B5
highlight%28x=-5%29
Good Luck,
tutor_paul@yahoo.com

Answer by MathTherapy(10699) About Me  (Show Source):
You can put this solution on YOUR website!
log 4x= log 5+log(x+1)

Other person's solution. x = - 5. is EXTRANEOUS, so there are NO SOLUTIONS to this equation!
For a VALID solution, x MUST be > 0