SOLUTION: How do you solve: 2^3x-2 = √128

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Question 782248: How do you solve:
2^3x-2 = √128
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
2^(3x - 2) = √128
2^(3x - 2)= 2^(7/2) {changed 128 to have a base of 2 and an exponent of 7/2}
3x - 2 = 7/2 {since bases are equal, set the exponents equal to each other}
3x = 11/2 {added 2 to each side}
x = 11/6 {divided each side by 3}

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